11[3-(2-2x)]+10x=4(8x+3)-1

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Solution for 11[3-(2-2x)]+10x=4(8x+3)-1 equation: 


Simplifying
11[3 + -1(2 + -2x)] + 10x = 4(8x + 3) + -1
11[3 + (2 * -1 + -2x * -1)] + 10x = 4(8x + 3) + -1
11[3 + (-2 + 2x)] + 10x = 4(8x + 3) + -1

Combine like terms: 3 + -2 = 1
11[1 + 2x] + 10x = 4(8x + 3) + -1
[1 * 11 + 2x * 11] + 10x = 4(8x + 3) + -1
[11 + 22x] + 10x = 4(8x + 3) + -1

Combine like terms: 22x + 10x = 32x
11 + 32x = 4(8x + 3) + -1

Reorder the terms:
11 + 32x = 4(3 + 8x) + -1
11 + 32x = (3 * 4 + 8x * 4) + -1
11 + 32x = (12 + 32x) + -1

Reorder the terms:
11 + 32x = 12 + -1 + 32x

Combine like terms: 12 + -1 = 11
11 + 32x = 11 + 32x

Add '-11' to each side of the equation.
11 + -11 + 32x = 11 + -11 + 32x

Combine like terms: 11 + -11 = 0
0 + 32x = 11 + -11 + 32x
32x = 11 + -11 + 32x

Combine like terms: 11 + -11 = 0
32x = 0 + 32x
32x = 32x

Add '-32x' to each side of the equation.
32x + -32x = 32x + -32x

Combine like terms: 32x + -32x = 0
0 = 32x + -32x

Combine like terms: 32x + -32x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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